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1 month, 1 week ago

When a certain photosensitive surface is illuminated with monochromatic light of frequency $\nu$ , the stopping potential for the photo current is $- \frac{V_{0}}{2}$ . When the surface is illuminated by monochromatic light of frequency $\frac{\nu}{2}$ , the stopping potential is $- V_{0}$ . The threshold frequency for photoelectic emission is :

• Option 1)

2$\nu$

• Option 2)

$\frac{3\nu}{2}$

• Option 3)

$\frac{4\nu}{3}$

• Option 4)

$\frac{5\nu}{3}$

Answered 4 weeks, 1 day ago
Stopping Potential /Cut-off Potential - It is defined as the potential necessary to stop any electron from reaching the other side. -   For v frequency stoping potential is For frequency stoping potential is -v0 So for frequency For    frequency From 1 and 2 We get so Option 1) 2Option 2)Option 3)Option 4)
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