Engineering

7 Views |
3 days, 1 hour ago

Let where Then equals :

- Option 1)
- Option 2)
- Option 3)
- Option 4)

As we have learnt in
Double Angle Formula -
- wherein
These are formulae for double angles.
Option 1)
Option 2)
Option 3)
Option 4)

Engineering

2 Views |
6 days, 4 hours ago

Sir

request you to kindly explain

Regards

Anushka

9318364602

Engineering

37 Views |
1 week, 3 days ago

Sir please tell the answer of this question and solving method.
Two particles executes S.H.M. of same amplitude and frequency along the same straight line. They pass one another when going in opposite directions, and each time their displacement is half of their amplitude. The phase difference between them is

Engineering

52 Views |
2 weeks, 1 day ago

If an equilateral triangle, having vertex at the (2,-1), has a side along the line, x+y=2, then the area (in sq. units) of this triangle is :

- Option 1)
- Option 2)
6

- Option 3)
- Option 4)

Engineering

77 Views |
2 weeks, 1 day ago

If the sum of the first 15 terms of the series 3+7+14+24+37+.......is 15K, then k is equal to :

- Option 1)
126

- Option 2)
122

- Option 3)
81

- Option 4)
119

Use
Summation of series of natural numbers -
- wherein
Sum of first n natural numbers
and
Summation of series of natural numbers -
- wherein
Sum of squares of first n natural numbers
3+7+14+24+37 ----------15K
Let Tn=an2+bn+c because difference is in A.P: [4,7,10,13-----------------]
at n=1 ------(i)
n=2 -------(ii)
n=3 -------(iii)
...

Engineering

73 Views |
2 weeks, 1 day ago

Statement 1: An equation of a common tangent to the parabola and the ellipse is

Statement 2: If the line is a common tangent to the parabola

and the ellipse then m satisfies

- Option 1)
Statement 1 is false, statement 2 is true

- Option 2)
Statement 1 is true, statement 2 is true; statement 2 is a correct explanation for statement 1

- Option 3)
Statement 1 is true, statement 2 is true; statement 2 is not a correct explanation for statement 1

- Option 4)
Statement 1 is true, statement 2 is false

As we learnt in
Equation of tangent -
- wherein
Tengent to is slope form.
Statement 1 :
Statement 2 :
If is a common tangent to and ellipse
From (i) statement 2 is a correct explanation for statement 1.
Option 1)
Statement 1 is false, statement 2 is true
This option is incorrect.
Option 2)
Statement 1 is true, statement 2 is true; statement 2 is a correct...

Engineering

73 Views |
2 weeks, 2 days ago

The eccentricity of an ellipse whose centre is at the origin is

If one of its directrices is x=−4, then the equation of the normal to it at

is:

- Option 1)
- Option 2)
- Option 3)
- Option 4)

As learned in concept
Eccentricity -
- wherein
For the ellipse
and
Equation of directrices -
- wherein
For the ellipse
we have & x=-4
From this we can calculate the value of a
so a=4
Now,
Hence, Equation of ellipse is-
Differentiate to get the value of slope-
So slope at given point is
Now by using the formula of normal of a equation-
normal at point is ...

Engineering

40 Views |
2 weeks, 2 days ago

Let G be the geometric mean of two positive numbers a and b, and M be the arithmetic mean of and

if is 4:5 then a:b can be:

- Option 1)
- Option 2)
- Option 3)
- Option 4)

As we learnt in
Arithmetic mean of two numbers (AM) -
- wherein
It is to be noted that the sequence a, A, b, is in AP where, a and b are the two numbers.
and
Geometric mean of two numbers (GM) -
- wherein
It is to be noted that a,G,b are in GP and a,b are two non - zero numbers.
Given G2 = ab
and
Option 1)
Option 2)
Option 3)
Option 4)

Engineering

103 Views |
2 weeks, 2 days ago

The sum of the first 20 terms common between the series 3+7+11+15+..... and 1+6+11+16+..... , is :

- Option 1)
4000

- Option 2)
4020

- Option 3)
4200

- Option 4)
4220

Use
Sum of n terms of an AP -
and
Sum of n terms of an AP
- wherein
first term
common difference
number of terms
series are 3,7,11,15,19,23,27,31..............
and 1,6,11,16,21,26,31....................
So common terms are 11,31,............
Option 1)
4000
Option 2)
4020
Option 3)
4200
Option 4)
4220

Engineering

65 Views |
2 weeks, 2 days ago

Find the last three digits of 17^256

@Shekhar
Solution: We have 172
Now, 17256
2 128
= (17 )
289
= (290 - 1)128
-290
- (128) (290) +1
128C
2
126(290)
12SC127(290) + 1
, where m is a positive integer.
= 1000 m + (128) (290) [(127) (145) - 1] + 1 = 1000 m + (128) (290) (18414) + 1
= 1000 Cm + 683527] + 680 + 1 = 1000 [m + 683527] + 681
Thus, the last three digits of 17256 are 681

Engineering

64 Views |
2 weeks, 3 days ago

which interval probability lies.

@_Rakesh,
Minimum value of probability of an event is 0 and maximum ia 1.
Probabilty of an event or intervel lies in [0,1]

Engineering

59 Views |
2 weeks, 3 days ago

find the general trem in the expansion of

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