Q
Engineering
2 months ago

# Point charge Q in fixed on (d, 0, 0) another charge Q is placed at (0, 0, 0). What should be the value of q sothat Q at origin will be in e

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A Avinash Dongre
Answered 1 week, 4 days ago

given F on Q at 0 = zero

$\therefore \frac{KQq}{\left ( \frac{d}{2} \right )^{2}} + \frac{kQ^{2}}{d^{2}} = 0$

4 q = - Q

$q = \frac{-Q}{4}$

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