Q&A - Ask Doubts and Get Answers

Engineering

2 months, 3 weeks ago

If an equilateral triangle, having vertex at the (2,-1), has a side along the line, x+y=2, then the area (in sq. units) of this triangle is :

- Option 1)
- Option 2)
6

- Option 3)
- Option 4)

60 Views

ACCORDING TO QUESTION ,WE JUST HAVE TO FIND THE PERPENDICULAR DISTANCE OF POINT (2,-1) FORM THE LINE

x + y = 2,THIS PERPENDICULAR DISTANCE IS EQUAL TO THE HEIGHT OF THE TRIANGLE FORMED,AND THEN WE CAN CALCULATE THE SIDE OF TRIANGLE,AND THEN BY APPLING FORMULA OF AREA OF TRIANGLE **{(1/2)*b*h}**

SO,

DISTANCE OF POINT FRON THE LINE (h) =

AND ALSO WE KNOW THAT HEIGHT OF THE TRIANGLE =

NOW, h = AND ALSO h =

FROM HERE WE GET THE VALUE OF a(BASE OF TRIANGLE(b)) =

NOW BY FORMULA **{(1/2)*b*h} = (1/2) * ** * = sq.units.

BUT UNFORTUNATELY NO OPTION IS MATCHING OUR ANSWER.SO, THE ANSWER IS 1/2

Option 1)

Option 2)

6

Option 3)

Option 4)

- Q. Stuck here, help me understand: - Electromagnetic Induction and Alternating currents - JEE Main
- Q. Solve this problem - Co-ordinate geometry - JEE Main-4
- Q. what is meant by chiral carbon?
- Q. How to solve this problem- - Limit , continuity and differentiability - JEE Main-4
- Q. Stuck here, help me understand: - Organic Compounds containing Halogens - JEE Main

Knockout AEEE JEE Main May BUY NOW

Exams

Articles

Questions